This preview shows page 1. Sign up to view the full content.
Unformatted text preview: this series converges alternating series test as it is clearly alternating, decreasing, and the limit goes to 0. This means we can also include ‐1 in our interval. This makes our interval of convergence [‐1,1] Example 3 2n( x 3) n
Determine the interval of convergence for the following: 5n
n 1 Here we see no functions to functions, so we will use the ratio test. an 1
2(n 1)( x 3) n 1 5n lim lim
n 1 2n( x 3) n n a
n 5 n
(n 1)( x 3) lim
n an 1 | x 3 |
5 n n
n lim T...
View Full Document