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Unformatted text preview: HCO CO H 3 2 2
CO3 H K K
K= a1 a 2 H 2CO3 Divide TOTCO3 Equation by [H2CO3]: H 2 CO3 K K a1 a22 H 2CO3 1 2 TOTCO H CO HCO CO3 3
3 2 3 + H 2CO3 H 2CO3 H 2CO3 H 2CO3 K
KK 1 a1 a1 a 2 2
H H H
K
KK
2 CO3 1 a1 a1 a 2 H 2 H TOTCO3 Fraction as given species 1.0
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0.0
3 4 H2CO3 5 6 HCO3 7
pH 8 9 10 CO32 11 12...
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 Winter '12
 Benjamin
 Equilibrium, Pk

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