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Unformatted text preview: Midtermi 5 01W; 1. An airport control tower sees an airplane hit the ground at a distance 20 km from the
tower, and at an angle 135° clockwise from north of the tower. It locates a rescue
helicopter at an elevation 0.75 km, at a horizontal distance 15 km from the tower, and at
an angle 150° clockwise from north of the tower. 3) Write the displacement vector from the helicopter to the airplane. (Let the xaxis be
east, the y—axis be north and the zaxis be vertical.) '
b) What is the distance from the helicopter to the airplane? Posi‘tim o—l airplane
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b) Dis mm! d: : (9.75 km 2. A truck of mass M = 3000 kg sits on an icy freeway at the top of a mountain pass. The
freeway descends a height H = 2.5 km over a horizontal distance L = 25 km, as shown.
a. What magnitude P of force, aimed up the hill as shown, will hold it in place? Give the
answer in both Newtons and pounds. (1 N = 0.2248 lbs)
b. If the truck is let go, and slides without rolling down the icy, frictionless hill, how
long will it take to get to the bottom?
0. How fast will it be moving, in km/hr, when it reaches the bottom? c) V: at: SSRGW :l1935%9
: 2 Vng 0'  .. .. 7. .M  l
, Zx‘iﬁxmo ’ 7"??? 7‘75‘1 hM/hr Fm' spring of spring constant K, which
extension of the spring from its relaxed (equilibrium) length. a. Find an expression for the acceleration a of the masses as a function of the extension
Ax, as well as M1, M2, K and g. b. Find an expression for the tension T in the rope in terms of Ax, M1, M2, K and g. Lei: +x be lo 4N right
(up alone] the VWM 32611;“) : HM
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— (AX—M1 , h.+m_( l) '3
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Pa H H.+H7, 3@ 3 mm, in”; Hl‘l‘l'lz( KA‘; +“ 1‘9) j 4. A student sitting at a height h = 3 In throws a projectile with velocity v0 making an initial
angle 9 = 45° to the horizontal. What must the magnitude of V9 be so that the projectile
hits an object P that is a horizontal distance D = 7 In from the student and at a height H =
4 m above the ground?   _,I z
H_h +v03met ijt v0 c056 t = D
2; "b: D/vocosé PW 9:457” Tana: l and $919271 3‘0 H: h+D “32: Va Solve ‘lTV v0 0&5 1L0H0W’:
+4113:— : +D “H
W" 11>: v 5 D1
V01: h+D~H Oh— blDH
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This note was uploaded on 04/07/2008 for the course PHYS 47020 taught by Professor Lawrence during the Fall '07 term at UC Irvine.
 Fall '07
 Lawrence
 Physics

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