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Hand In 12 Solutions (07)

# Hand In 12 Solutions (07) - Solutions for Hand-In Set#12...

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Solutions for Hand-In Set #12 PHYS 212 – Spring 2007 Supplemental Reading — 5.4 To complete this problem, use the same steps as in 5.3, but in reverse: use “distance = speed × time” (with c as a speed) to get an estimate of Δ t ; then use the time- energy uncertainty principle to get an estimate of Δ E , and thereby m . If the range is 100 m, then the typical lifetime of the virtual particle would be t = d c = 100 m 3 × 10 8 m/s = 3 . 3 × 10 - 7 s . The energy-time uncertainty principle, Δ E Δ t ¯ h gives Δ E = ¯ h Δ t = 6 . 63 × 10 - 34 J · s 2 π × 3 . 33 × 10 - 7 s = 3 . 17 × 10 - 28 J = 1 . 98 × 10 - 9 eV . So the mass of the hypothetical particle would be about m = 2 × 10 - 9 eV/ c 2 . Supplementary Reading — 5.11 e - ν e W - e - ν e + W - ν e W - e - ν e + W - e - W - ¯ ν e W + ¯ ν e e + e - + ¯ ν e W - e - μ ν μ W - e + ¯ ν e + W + μ - ν μ + W - Supplementary Reading — 5.12 μ + ¯ ν μ W + Ru quark Bu quark R ¯ B gl Rs quark ¯ R ¯ u quark W -

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Supplementary Reading — 6.2 (a) Strategy: Break the hadrons into quarks: d ¯ u + uds s ¯ u + ddu . Look for the quarks that are just going through without changing. Take a look here — there are 2 d s on the left and 2 d s on the right. There is an anti- u on the left and one on the right, there is a u on both the
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Hand In 12 Solutions (07) - Solutions for Hand-In Set#12...

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