41gm molcaoh 2 2 molhcl be sure to factor in the ratio

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Unformatted text preview: lCa(OH ) ⎞ 2 ⎟(0.2 molHCl) = 7.41gm ⎜ ⎟⎜ ⎝ molCa(OH ) 2 ⎠⎝ 2 molHCl ⎠ be sure to factor in the ratio of stoichiometric coefficients correctly- it helps to write out the units _____ gm Ca(OH)2 Ionic and polar covalent bonds 3. (10 pts) The bond in a diatomic molecule has a bond length of 3.00 Å and a dipole moment of 2.00 Debye. Calculate the charge on the positive end of the molecule, in Coulomb units. 2.0 D = δ (3.0 Å)/(0.2082 Å/D) δ = (2.0 D)(0.2082 Å/D)/(3.0 Å) = 0.139 (fractional charge) 0.139 (1.602 x 10-19 C) = 0.222 x 10-19 C _______ C 4. (10 pts) The cost of making ions...
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