Unformatted text preview: 2 04P b+2 b. (8 pts) Molecular formulas.
By combustion analysis, a chemical compound is found to have the follow mole ratios of
1 C : 0.714 H : 0.429 N : 0.857 O
From measurements of the grams of compound present as a gas in a particular volume, the
molecular mass is computed as 227.1 gm/mol. What is the molecular formula of the compound?
(You may round atomic masses to one decimal place.)
the molecular weight must be an integral multiple of:
(1*12.0 + 0.714*1.0 + 0.429*14.0 + 0.857*16.0) = 32.43 gm/mol
227.1/32.43 = 7.00
The molecular formula is therefore C7 H5 N3 O6 (trinitrotoluene) C____ H____ N ____ O_____ Name: ___________________...
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This note was uploaded on 02/07/2014 for the course CHEMISTRY 030.101 taught by Professor Draper during the Spring '06 term at Johns Hopkins.
- Spring '06