Lecture_4_motifs

0336 ctataaaccttacat 12 x 78 x 12 x 58 x 14 x 78 0299

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Unformatted text preview: the highest probability of being created from the profile P 7/8 3/8 P- Most Probable L- mer 1/8 A Probability of a different string: Prob(atacag | P) = 1/2 x 1/8 x 3/8 x 5/8 x 1/8 x 1/8 = .001602 7/8 3/8 0 1/8 1/8 0 1/2 5/8 3/8 0 T 1/8 1/8 0 0 1/4 7/8 G P = 1/2 C 0 1/4 0 1/8 3/8 1/4 1/8 Given a sequence = ctataaaccYacatc, find the P- most probable L- mer 3 9/4/13 P- Most Probable L- mer P- Most Probable L- mer Compute Prob( a | P ) for every possible 6- mer: A 1/2 7/8 3/8 0 1/8 C 1/8 0 1/2 5/8 3/8 0 0 String, Highlighted in Red Calculations Prob(a|P) T 1/8 1/8 0 0 1/4 7/8 ctataaaccttacat 1/8 x 1/8 x 3/8 x 0 x 1/8 x 0 0 G 1/4 0 1/8 3/8 1/4 1/8 ctataaaccttacat 1/2 x 7/8 x 0 x 0 x 1/8 x 0 0 ctataaaccttacat 1/2 x 1/8 x 3/8 x 0 x 1/8 x 0 0 ctataaaccttacat 1/8 x 7/8 x 3/8 x 0 x 3/8 x 0 0 ctataaaccttacat 1/2 x 7/8 x 3/8 x 5/8 x 3/8 x 7/8 .0336 ctataaaccttacat...
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This note was uploaded on 02/10/2014 for the course CS 425 taught by Professor Asaben-hur during the Fall '13 term at Colorado State.

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