Assignment 2 Outline

# Comp 1012 winter 2014 assignment 2 page 2 of 9

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ivescience.com/18749- human- brain- cell- number.html], about when will a computer chip have as many transistors as a brain has neurons, if Moore’s Law continues to hold?1 Start with the number of transistors on the Haswell processor in 2013. 1 Brain neurons and computer transistors are not strictly comparable, since a transistor has only three connections, and a neuron can have thousands, but this type of comparison shows the machines are catching up. COMP 1012 Winter 2014 Assignment 2 Page 2 of 9 Question 2—Chain Fence [9 marks] Description A chain or rope suspended at two points hangs in a curve called a catenary; such a chain is sometimes used as a fence, as in Figure 1(a). In this question you will determine the shape when a chain of a given length is suspended between two supports about 2 metres apart, as in Figure 1(b). You will determine what the total force is on a support for various lengths of chain (long chains are heavy and have a significant downward force; shorter chains are taut and pull the supports toward one another). Finally you will find the approximate length of chain that has the minimum total force on each support. Figure 1: Chain Fence. (a) Photo. (b) Diagram for d = 0.98m, h = 1.1m, various chain lengths. Theory Shape of the Catenary The catenary is in the shape of the cosh function.2 If the origin (that is, x = 0) is in the middle between two support posts at ±d, the position of a point (x, y) on the hanging chain is given by the following equation between x and y. (1) = + cosh cosh Here h is the height of the points of support [m], the support posts are located at x = ±d [m], and a is a parameter [m] that determines how low the chain sags, and how long it is. Finding the Length of the Chain for a given...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern