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Unformatted text preview: n −1 = b2 sx 2 y = −32 + 5 / 9 x = −32 + 5 / 9(835.00) = 431.89 °C s y = b 2 s x = (5 / 9) 2 (10.5) 2 = 34.028 °C
2 2 6100. Using the results found in Exercise 698 with a = − x
and b = 1/s, the mean and standard deviation
s of the zi are z = 0 and sZ = 1. 6101. Yes, in this case, since no upper bound on the last electronic component is available, use a
measure of central location that is not dependent on this value. That measure is the median.
Sample Median = x ( 4 ) + x (5)
2 = 63 + 75
= 69 hours
2 660 n +1 6102 a) x n +1 = x n +1
x n +1 b) n ∑ xi ∑x i =1 i =1 i + x n +1 =
n +1
n +1
nx n + x n +1
=
n +1
x
n
=
x n + n +1
n +1
n +1 2
ns n +1 ⎛n
⎞
⎜ ∑ xi + x n +1 ⎟
n
⎠
2
= ∑ xi2 + x n +1 − ⎝ i =1
n +1
i =1 2 2 n
⎛n ⎞
⎜ ∑ xi ⎟
2 x n +1 ∑ xi
n
x2
i =1
⎠−
2
i =1
− n +1
= ∑ xi2 + x n +1 − ⎝
n +1
n +1
n +1
i =1 ⎛n ⎞
⎜ ∑ xi ⎟
n
n
n2
2
2x n +1 x n − ⎝ i =1 ⎠
x n +1 −
= ∑ xi +
n +1
n +1
n +1
i =1 2 ⎡n
(∑ xi )...
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This document was uploaded on 02/09/2014.
 Spring '14

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