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7 pt 1 pin 03 10 mw 3mw 2 friis equation

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Unformatted text preview: cm S11=- 1.5 dB At Half max power : d’= 2.3 cm Freq= 12.5 GHz IV. Estimations: 1) s11 = 10 log(Γ) ⇔ Γ = 10 s11 10 = 0.7 Pt = (1 − Γ) ⋅ Pin = 0.3 × 10 mW = 3mW 2) Friis Equation : Pr = Pt ⋅ G ² ⋅ ( With path loss L = 10 log( Gain G = Pr λ Pt ⋅ ( )² 4πD λ )² 4πD Pt ) = 23dB Pr = 3.89 = 5.9dB 3) 1 Aeff = G ⋅ λ² = 1.78 ⋅ 10 −4 m² 4π 4) Let the Beamwidth ϴ² d' = 0.23 D → θ = 0.45rad tan(θ / 2) = Directivity : D = V. 4π = 63 = 17.9dB θ² Conclusion From the data measured, we were able to compute the gain of the Rx antenna thanks to Friis transmission equation and to deduce the effective antenna area, the half beam width and the directivity of the antenna. We can note that horn antennas have a high directivity, which means that they are to receive signal from a pretty fixed direction. 2...
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