Unformatted text preview: relativistic formula for the magnitude
of momentum is Clearly, a x(0) = 0 : prel = m v = p non
: Find a y(0) : So we need to nd Correct answer: 6.
Explanation:
Taking the y component of the acceleration:
a y(0) = 6 : =s :
1 1 0:999 c
c = 22 :3663:
2 Now we can plug in:
Find a z(0) :
Correct answer: 0.
Explanation:
Taking the z component of the acceleration:
a z(0) = prel = p non
= (22 :3663)(5 :01398 10−19 kg m =s)
= 1 :12144 10−17 kg m =s : 42(0) = 0 : A proton in an accelerator is traveling at a
speed of 0 :999 c. If you use the approximate
nonrelativistic formula for the magnitude of
momentum of the proton, what answer do you
get? Answer in kg m =s. (The mass of the
proton is 1 :673 10−27 kg)
Your answer must be within
5.0%
−19
Correct answer: 5 :01398 10
kg m =s.
Explanation:
The approximate nonrelativistic formula
for the magnitude of momentum is
pnon = m v:
Plugging in, we obtain
pnon = (1 :673 10−27 kg)(0 :999 3
= 5 :01398 10−19 kg m =s : 108 m =s) The approximate value from part 1 is significantly too low. Approximately, what is the
ratio of magnitudes:
prel
=?
pnon
Your answer must be within
Correct answer: 22 :3663. 5.0% Explanation:
We just take the ratio of our answers:
prel
1:12144
=
pnon 5:01398 10−17
10−19 kg m =s
= 22 :3663 :
kg m =s...
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This note was uploaded on 02/11/2014 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas.
 Spring '08
 Turner
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