Tutorial08-sol(1)

# 5 s the line segment from 1 0 to 0 1 can be

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ) S The line segment from (1 0) to (0 1) can be parameterized by 0 ≤ 1 − . On this line segment, part of the integral becomes 1 The line segment from (0 1) to (−1 0) can be parameterized by −1 ≤ ≤ 0 − . On this line segment, part of the integral becomes −1 −1 = −1+ = = −2 (−1 + ) + (− ) =0 |−1+ |+|− | The line segment from (0 −1) to (1 0) can be parameterized by −1 ≤ On this line segment, part of the integral becomes 0 = −1 The line segment from (−1 0) to (0 −1) can be parameterized by 0 ≤ ≤ 1 − . On this line segment, part of the integral becomes 0 = −1− 0 (− 1 − ) + (− ) = −2 |−1− |+|− | 1 = (1 − ) + =0 |1 − | + | | 0 0 ≤1 (1 + ) + =2 |1 + | + | | ≤0 = 1+ . 0 =2 −1 Thus, we conclude that C E + =0−2+0+2=0 | |+| | :) Evaluate 2 2 + + 2...
View Full Document

Ask a homework question - tutors are online