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can be arranged to get the sequence 10,11,12,13,1 (because, by tradition, the 1 card, or “ace,” can
act as either the highest or lowest number). For example, the outcome {3D, 4H, 5H, 6S, 7D} is an
element of STRAIGHT. Find P (FULL HOUSE) and P (STRAIGHT). Solution: The sample space is Ω = {A : A ⊂ C and A = 5}, and the number of possible
outcomes is Ω = 552 . To select an outcome in FULL HOUSE, there are 13 ways to select a
number for the three cards with the same number, and then 12 ways to select a number for the
other two cards. Once the two numbers are selected, there are 4 ways to select 3 of the 4 suits
3
for the three cards with the same number, and 4 ways to select 2 of the 4 suits for the two cards
2
with the other number. Thus, P (FULL HOUSE) =
=
= 13 · 12 · 4
3 4
2 52
5 13 · 12 · 4 · 4 · 3 · 5 · 4 · 3 · 2
2 · 52 · 51 · 50 · 49 · 48
6
6
=
≈ 0.0014.
15 · 5 · 49
4165 To select an outcome in STRAIGHT, there are ten choices for the set of ﬁve integers on the
ﬁve cards that can correspo...
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This note was uploaded on 02/09/2014 for the course ISYE 2027 taught by Professor Zahrn during the Spring '08 term at Georgia Tech.
 Spring '08
 Zahrn
 The Land

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