Using Table to Graph Lines Exs

A funcon may have zero or one yintercepts now we have

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Unformatted text preview: epts. x and y ­intercepts We can also see that the x and y intercepts are both the point (0,0). The x ­intercept is where the graph of the func+on crosses the x ­axis, or the point when y = 0. A func+on may have no x ­intercepts, or may have many. The y ­intercept is where the graph of the func+on crosses the y ­axis, or the point when x = 0. A func+on may have zero or one y ­intercepts. Now, we have all the informa+on we need to graph this linear func+on. We graph on a rectangular coordinate system called the Cartesian coordinate system. It looks like this: Graph of y = x To graph a linear equa+on, you must: Graph of y = x To graph a linear equa+on, you must: •  Plot the x and y ­intercepts (if they exist). Graph of y = x To graph a linear equa+on, you must: •  Plot the x and y ­intercepts (if they exist). •  Plot at least two other points. Graph of y = x To graph a linear equa+on, you must: •  Plot the x and y ­intercepts (if they exist). •  Plot at least two other points. Using the table, the graph of y = x looks like this: Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Solu+on: We must first solve for y in the equa+on. Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Solu+on: We must first solve for y in the equa+on. 4y = 3x – 6 Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Solu+on: We must first solve for y in the equa+on. 4y = 3x – 6 y = (3/4)x – 3/2 Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Solu+on: We must first solve for y in the equa+on. 4y = 3x...
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This note was uploaded on 02/10/2014 for the course MATH 133 taught by Professor Johnson during the Spring '11 term at American InterContinental University.

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