Using Table to Graph Lines Exs

Let us plug in x 6 into the equaon graph of 3x 4y

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 = x Therefore, the x ­intercept is (2,0). Now, we will find the y ­intercept by plugging in x = 0 into the equa+on and solving for y. y = (3/4)(0) – 3/2 Graph of  ­3x + 4y =  ­6 Example. Graph  ­3x + 4y =  ­6. Solu+on: We must first solve for y in the equa+on. 4y = 3x – 6 y = (3/4)x – 3/2 Now, we will find the x ­intercept by plugging in y = 0 into the equa+on and solving for x. 0 = (3/4)x – 3/2 3/2 = (3/4)x 2 = x Therefore, the x ­intercept is (2,0). Now, we will find the y ­intercept by plugging in x = 0 into the equa+on and solving for y. y = (3/4)(0) – 3/2 y =  ­3/2 Therefore, the y ­intercept is (0, ­3/2). Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Let us plug in x = 6 into the equa+on. Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Let us plug in x = 6 into the equa+on. y = (3/4)(6) – 3/2 = 9/2 – 3/2 = 6/2 = 3 Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Let us plug in x = 6 into the equa+on. y = (3/4)(6) – 3/2 = 9/2 – 3/2 = 6/2 = 3 Therefore, another point that sa+sfies the equa+on is (6, 3). Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Let us plug in x = 6 into the equa+on. y = (3/4)(6) – 3/2 = 9/2 – 3/2 = 6/2 = 3 Therefore, another point that sa+sfies the equa+on is (6, 3). Let us plug in x =  ­6 into the equa+on. Graph of  ­3x + 4y =  ­6 Now we must find at least two addi+onal points. Let us plug in x = 6 into the equa+on. y = (3/4)(6) – 3/2 = 9/2 – 3/2 = 6/2 = 3 There...
View Full Document

Ask a homework question - tutors are online