Assignment 3 Fall 2013_SOLN_revised

# 05 005 s mgl 163 232 warm weather condition k167c

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Unformatted text preview: dtw (/d) 0.05 0.05 S (mg/l) 16.3 23.2 Warm weather condition: K16.7C = K20C Φ 20.4C - 20C= 6/d (1.06)20.4C - 20C= 6.1/d Kd16.7C = Kd20C Φ 20.4C - 20C= 0.07/d (1.06)20.4C - 20C= 0.07/d Cold Weather: Xm = Y(So-S)/ (1+ kdӨc) = 0.65(200mg/L - 16.3 mg/L)/ (1+ 0.05*3d) = 103.8 mg/L Px= Q(1+ fdKdӨc) Xm = 3800m3/d ( 1 + 0.15 * 0.05* 3) * 103.8 mg/L * 1000 L/m3 * 1kg/10^6mg Px= 403.3 kg/d PxTSS = 403.3 kg/d/ 0.85 = 474.5 kgTSS/d O2r = Q(So-S)- 1.42Px = 3800 m3/d (200- 16.3mg/l)/1000 - 1.42(403.3kg/d) = 125.4 mg/L Warm Weather: Xm = Y(So-S)/ (1+ kdӨc) = 0.65(200mg/L - 11.3 mg/L)/ (1+ 0.07*3d) = 101.4 mg/L Px= Q(1+ fdKdӨc) Xm = 3800m3/d ( 1 + 0.15 * 0.07* 3) * 101.4 mg/L * 1000 L/m3 * 1kg/10^6mg Px= 397.3 Px...
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