Assignment 3 Fall 2013_SOLN_revised

6 biokinetics at operating temperature k 45 d 1 ks 75

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: COD/BOD5 = 1.6 Biokinetics (at operating temperature) K 4.5 d-1 Ks 75 mg bCOD/L Y 0.45 mg VSS/mg COD kd 0.1 d-1 fd 0.15 mg VSS/mg VSS Assume VSS/TSS for grown biomass = 0.85 a. Total suspended solids concentration in the aeration basin Solution: Xio = nbVSS = (1- bpCOD/pCOD)VSS bCOD = 1.6BOD5 = 1.6 (300mg/l) = 480 mg/l =So pCOD = COD- sCOD = 600mg/l - 315mg/l= 285mg/L bsCOD= 1.6sBOD5 = 1.6 (150mg/l) = 240mg/l bpCOD = bCOD- bsCOD = 480mg/l - 240mg/l = 240mg/l Xio = nbVSS = (1- bpCOD/pCOD)VSS = (1 - (240mg/l / 285mg/l)) 325mg/l= 51.3 mg/l vss FSS = TSS- VSS = 400 mg/l - 325mg/l = 75mg/l b. Mass flow of volatile suspended solids in the waste stream Solution: c. Oxygen requirements OUR = Q (So-S) - 1.42Pxvss growth = 65000 m3/d(480mg/l - 13mg/l)(1000l/m3)(1kg/10^6mg) - 1.42(9789.5kgVSS/d) = 16453.9 kg /d...
View Full Document

This document was uploaded on 02/10/2014.

Ask a homework question - tutors are online