Assignment 4 Fall 2013 Soln

11 20c sdnr 15c 011 1026 5 0097 nor nox ce

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Unformatted text preview: NR@ 15C = 0.11 * 1.026^(-5) = 0.097 NOr = NOx - Ce = 25 - 4.25 = 20.25 mg/L 20.25 mg/L * (1000 L/m^3) (1000m^3/f_ = 20.25x10^6 mg/d V anoxic = 20 x 10^6 / (0.097 x 1620 mg/L * 1000L/m^) = 127 m3 Iterate Guess V anoxic = 127m3 F/Mb = 0.972 SDNR = 0.13 SDNR15= 0.11 Vanoxic = 108 m^3 Guess Vanoxic = 108 m^3 F/Mb= 1.14 SDNR = 0.16 SDNR15= 0.14 Vanoxic = 88.17 continue iterating Final: V= 44.7 F/Mb=2.8 SDNR=0.3 SDNR15= 0.26 Vanoxic = 47.4 m3 Close enough!! You can also design on the basis of HRT. You could have chosen to iterate for NOr (instead of basin volume)...
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