To find such a vector we have to find one of the many

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Unformatted text preview: atrix we get: , and is free In order to get one of many possible solutions let’s fix and . Hence we get: . Part (e) ( ) ( ) ( ( )( ) ( ) ) According to the definition of perpendicular vectors one of many possible answers is: ( )...
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This note was uploaded on 02/13/2014 for the course CS 132 taught by Professor Kfoury during the Fall '13 term at BU.

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