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Unformatted text preview: The kernel of (b) iff . }
has two matrices)
such as also is not injective because
[ { [ ] which is not
for example
. { } [
[ ] { {
}
The kernel of is a point so has no dimension.
Determinant of is
so as a transformation is bijective (both injective and
surjective). (d) [ { } [ 
}
is four (since there are four free variables). {
The dimension of kernel of For any or [ s.t. hence is a surjective transformation. is not injective since s.t. [ [ [ . (e) { } [
[ ] {
{( The kernel of s.t. is not injective because for any two point like
we have...
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This note was uploaded on 02/13/2014 for the course CS 132 taught by Professor Kfoury during the Fall '13 term at BU.
 Fall '13
 KFOURY
 Algorithms

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