as a transformation is not surjective because covered

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Unformatted text preview: The kernel of (b) iff . } has two matrices) such as also is not injective because [ { [ ] which is not for example . {| } [ [ ] { { } The kernel of is a point so has no dimension. Determinant of is so as a transformation is bijective (both injective and surjective). (d) [ {| } [ | } is four (since there are four free variables). { The dimension of kernel of For any or [ s.t. hence is a surjective transformation. is not injective since s.t. [ [ [ . (e) {| } [ [ ] { {( The kernel of s.t. is not injective because for any two point like we have...
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This note was uploaded on 02/13/2014 for the course CS 132 taught by Professor Kfoury during the Fall '13 term at BU.

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