hw5-solutions

B let be a vector in is and eigenvalue and whose

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Unformatted text preview: e a vector in is and eigenvalue and whose entries are all ’s. Doing the math we get is an eigenvector. (c) Using previous part we have is and eigenvalue of eigenvalue of as well. . Using part (a) we have is and . Hence Problem 3. (a) Assume is the corresponding matrix of transformation . Based on the definition of we have for all nonzero vectors on the line we have ( ) which means . Hence is one of eigenvalues of . let be a line through the origin that is prependecular to line . Each point on rotat...
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This note was uploaded on 02/13/2014 for the course CS 132 taught by Professor Kfoury during the Fall '13 term at BU.

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