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Unformatted text preview: . CO2 3. H+, H2O 2. B O C Purpose of the problem The toughest test: predicting the product. The sooner you get practice the better. Suggested solution Though prediction is harder than explanation, you should get these right the first time as only the last one has a hint of difficulty. In the first example, the ethyl Grignard reagent acts as a base to remove a proton from the alkyne. Whether you draw the intermediate as an alkyne anion or a Grignard reagent is up to you....
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