As the primary is chosen this must be sn2 hcl o oh o h

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Unformatted text preview: e used for SN2. Cl O Cl Cl O Cl HOMe O O Cl Me O OMe H The second compound has only one leaving group and that must be protonated before it can leave. It has two possible sites for attack by the nucleophile (Cl–), one primary and one secondary. As the primary is chosen, this must be SN2. HCl O OH O H Cl Cl Solutions for Chapter 15 – Nucleophilic Substitution at Saturated Carbon PROBLEM 3 Draw mechanisms for these reactions and give the stereochemistry of the product. 1. PhNMe2 CH2Cl2 O Br Cl + H 2N 2. NaH, DMF N O CO2Et...
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