This must be an sn1 rather than an sn2 at a t butyl

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Unformatted text preview: uestion suggests. Me N O Me O O Me + O O + N O Me With an unfamiliar reaction, it is best to identify the nucleophile and the electrophile and see what happens when we unite them. The nitrogen atom is obviously the nucleophile and one of the carbonyl groups must be the electrophile. Me N O Me O Me N Me O + O O O We must lose a t- butyl group from this intermediate to give one of the products and unite it with the acetate ion to give the other. This must be an SN1 rather than an SN2 at a t- butyl group....
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This document was uploaded on 02/10/2014.

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