Phy489Assignment1Solutions_2013

Such a process is a decay not a scattering process

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Unformatted text preview: y hadrons in the final state. Such a process is a decay, not a scattering process. You were meant to draw these. 2) In class, and in the assignment question I stated that by “lowest ­order” I mean lowest order in the interaction via which the reaction (scattering or decay) proceeds. As I’ve emphasized a number of times in the lectures, if you have e.g. a two ­vertex weak ­interaction or EM process with additional qq pairs in the final state produced via gluons...
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