Answers+to+Ch5

0075 moll 00075moll h2 h0025moll

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: .78 × 10−4/ 0.889 × 10−4 = (0.0160/ 0.0080)n ; 2.0 = 2.0n ; n = 1 3.56 ×10−4/ 0.889 × 10−4 = (0.040/ 0.020)p ; 4.0 = 2.0p ; p = 2 1st order in I− and BrO − 3 ; 2nd order in H+ (b) rate = k ×[BrO − 3 ] × [I− ] ×[H+ ]2 (c) k =0. 889×10−4 mol/L · s/(0. 00200 mol/L)(0. 0080 mol/L)(0. 020 mol/L)2 = 1. 4×104 L3 /mol3 · s (d) 5. 00 ×10−4 mol/L · s= 1. 4×104 L3/mol3 · s×0. 0075 mol/L ×0. 0075mol/L × [H+ ]2 [H+ ] = 0.025 mol/L 35. (a) The plot of ln[(CH3 )2 N2 ] vs t is a str...
View Full Document

Ask a homework question - tutors are online