Answers+to+Ch5

360min22s 73lnkuncat lnaeauncatrt lnkcatlnaeacatrt

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Unformatted text preview: 1/ [Ao ])/k=(1/ 0. 0915) − (1/ 0. 187) L/ mol/2. 65 L/ mol · min= 2.11 min (c) rate = (2.65 L/mol · min)(0.335 mol/L)2 = 0.297 mol/L · min 55. Decomposing 90% means [A] = 0.10[Ao ] t =(1/ [A] − 1/ [Ao ])/k=[(1/ (0. 10)(0. 02) − (1/ 0. 02)) L/ mol/ 48 L/ mol · min= 9.4 min 61. 65. Let k1 be the constant at 21℃and k2 the constant at 5◦ C. lnk1/k2=75 kJ/ mol/0. 00831 kJ/ mol · ( 1/278 K −1/294 K) k1/k2 = 5.9 4 Let t1 be the souring time at 21℃ and t2 the souring time at 5◦ C. k1/k2=t2/t1 t2 = 5.9(8 h) = 47 h...
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