Answers+to+Ch7

20 g 52 ml mhw chapter 15 3 67 ni2 nien 23

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Unformatted text preview: 7.40 ; [H+ ] = 4. 0×10−8 (a)[H2 CO3 ]/[HCO3- ]=[H+ ]/Ka H2 CO3=4. 0×10−8/ 4. 4×10−7 =0.091 (b)[ H2 CO3]/[ HCO 3- =0. 091/1; Assume [HCO 3- = 1.000 M , then [H2 CO3 ]= 0.091 M [HCO 3- ] after conversion to H2 CO3 = 1.000 – (0.15×1.000) = 0.85 M [H2 CO3] after conversion = 0.091 + (0.15 × 1.000) = 0.241 M [H+ ] = 4. 4 ×10−7 ×(0. 241/0. 85)= 1. 25×10−7 ; pH = 6.90 (c)...
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