Answers+to+Ch7

8 104 mol0 013 l 0 025 l 9 9 103 m q hg 22cl

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Unformatted text preview: /mol Lac−);mol HLac =(3. 2×10−5 )(2. 230)/1. 4 ×10−4 = 0.51 mass HLac = (0.51 mol)(90.1 g/mol) = 46 g ; mass HLac solution =46 g/0. 73= 63 g Volume HLac solution = (63 g)(1 mL/1.20 g) = 52 mL MHw Chapter 15 3. 67% Ni2+ → Ni(en ) 2+3 ; [Ni(en ) 2+3 ] = 67 ; Ni2+ = 100 − 67 = 33 2. 1×1018 =[ Ni(en ) 2+3]/[Ni2+ ][en ]3 =67/33 [en ]3 ; [en ] = 9. 9 ×10−7 M 9. (a) [OH...
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