Answers+to+Ch3-2

003gmol0166gl cdensityofco200414moll4401gmol182gl

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Unformatted text preview: n =(770 mmHg ×1 atm/760 mmHg)(1. 00 L)/(298 K × 0.0821(L ∙ atm/mol ∙ K))= 0.0414 mol density of air = (0.0414 mol/L)(29.09 g/mol) = 1.20 g/L (b) density of He = (0.0414 mol/L)(4.003 g/mol) = 0.166 g/L (c) density of CO2 = (0.0414 mol/L)(44.01 g/mol) = 1.82 g/L density of CO2 > density of air; balloon will not rise 33. 5. 85 L SO2×(1 L Cl2 O/1 L SO2)= 5.85 L Cl2 O; 9. 00 L Cl2 ×(1 L Cl2 O /2 L Cl2)= 4.50 L Cl2 O Cl2 is limiting; 4.50 L Cl2 O are produced; 9. 00 L Cl2×(1 L SO2/2 L Cl2)= 4.50 L SO2 react unreacted SO2 = 5.85 L ‐ 4.50 L = 1.35 L 35. (a) mol N2 O5 =(1. 00 atm)(1. 50 L)/(298 K)(0. 0821 L ∙ atm/ mol ∙ K) = 0.0613 mol H+ = 0. 0613 mol N2 O5×2 mol H+/ 1 mol N2 O5= 0.123 (b) M = 0.123 mol/0....
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This note was uploaded on 02/13/2014 for the course CHEM 1024 taught by Professor Dr.zhifengding during the Winter '12 term at UWO.

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