Answers+to+Ch3-2

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Unformatted text preview: 437 L = 0.281 mol/L 39. mol C3 H5 N3 O9 =10. 00 g/227. 1 g/mol= 0.04403 12 mol CO2 + 6 mol N2 + 10 mol H2 O + 1 mol O2 = 29 mol gas/4 mol C3H5N3 O9 2 ngas = (0.04403)(29/4) = 0.3192 mol; Vgas =(0. 3192 mol)(796 K)(0. 0821 L ∙ atm/ mol ∙ K)/1. 45 atm = 14.4 L 41. PCO2 =(95. 0/100 )×735mm Hg = 698 mm Hg; PO2 =(5. 0/100)×735 mm Hg = 37 mm Hg 43. Assume a 100‐g sample. mol CO2 = (92 g)(1 mol/44.0 g) = 2.1 ; mol NO = (3.6 g)(1 mol/30.0 g) = 0.12 mol SO2 = (1.2 g)(1 mol/64.1 g) = 0.019 ; mol H2 O = (4.1 g)(1 mol/18.0 g) = 0.23 total number of moles = 2.1 + 0.12 + 0.019 + 0.23 = 2.5 PCO2 = (2.1/2.5)(752 mm Hg) = 6.3 ×102 mm Hg; PNO = (0.12/2.5)(752 mm Hg) = 36 mm Hg PSO2 = (0.23/2.5)(752 mm Hg) = 5.7...
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