Veh when does the 100th car arrive 100 1008 125 min

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 12.5 min When does the 100th car departure: 10(t-10) = 100 ► t = 20min L μ = 10t λ = 8t 100 t 12.5 20 = 20 – 12.5 = 7.5 min = 7 min and 30 sec 5 CEE 362 - Homework #4 Solution Manual Problem # 5: Solution proportion of numbers have not been considered in the diagram for better illustration L 200 E = 2(t-30) 160 120 = 0(t-20) B C μ = 4t = 8t D A 20 min F 30 (min) 50 (min) (y-160) = (x-30)*2 y= 2x +100 we also know y = 4x x= 50, y = 200 total delay = sum of area between arrival lines and departure line [0.5*20*160] + [160*10] + [160*2] + [0.5*20*40] - [0.5 *50*200] = 1800 veh-min 6 t CEE 362 - Homework #4 Solution Manual Problem # 6: Given: Deterministic time varying rate Departure rate = μ = 2 veh / min = 2 veh /min Required: Time needed for the queue to clear Total delay = Maximum queue length Solution: Arrival: Departure: The time required to clear the queue with a departure rate of 2 veh/min will be: = ►t = 21.05 min = arrivals – departures = - 2t = + 2.3t + 2.3t = 0 t = 10.45 ►...
View Full Document

This document was uploaded on 02/11/2014.

Ask a homework question - tutors are online