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HW 4 Solution

# Veh when does the 100th car arrive 100 1008 125 min

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Unformatted text preview: 12.5 min When does the 100th car departure: 10(t-10) = 100 ► t = 20min L μ = 10t λ = 8t 100 t 12.5 20 = 20 – 12.5 = 7.5 min = 7 min and 30 sec 5 CEE 362 - Homework #4 Solution Manual Problem # 5: Solution proportion of numbers have not been considered in the diagram for better illustration L 200 E = 2(t-30) 160 120 = 0(t-20) B C μ = 4t = 8t D A 20 min F 30 (min) 50 (min) (y-160) = (x-30)*2 y= 2x +100 we also know y = 4x x= 50, y = 200 total delay = sum of area between arrival lines and departure line [0.5*20*160] + [160*10] + [160*2] + [0.5*20*40] - [0.5 *50*200] = 1800 veh-min 6 t CEE 362 - Homework #4 Solution Manual Problem # 6: Given: Deterministic time varying rate Departure rate = μ = 2 veh / min = 2 veh /min Required: Time needed for the queue to clear Total delay = Maximum queue length Solution: Arrival: Departure: The time required to clear the queue with a departure rate of 2 veh/min will be: = ►t = 21.05 min = arrivals – departures = - 2t = + 2.3t + 2.3t = 0 t = 10.45 ►...
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