645 04 735log10 11 1 006 log10 17 30 846 1

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Unformatted text preview: GO ON TO THE NEXT PAGE 9 CEE 362 - Homework #3 W18 = < 6,567,920 Solution Manual under designed Try D= 12 inch log10W18 1.645 * 0.4 7.35log10 12 1 - 0.06 log10 1.7 / 3.0 8.46 1 1.624 107 12 1 600 * 0.9 120.75 1.132 4.22 0.32 * 2log10 215.63 * 3.2 120.75 18.42 5000000 2000.25 W18 = 6.9562 W18 = W18 = = 12 > 6,567,920 :) inch is adequate 10 CEE 362 - Homework #3 Solution Manual Problem # 6: =6* lb / TSI = 2.5 = 432 psi ΔPSI = 4.7-2.5 = 2.2 SN = 4 K = 190 lb / = 0.8 J = 0.3 D = 10 in Rigid: 20 kip single = 1.58 42 kip tandem = 4.74 log10W18 Z R S o 7.35log10 D 1 - 0.06 log10 PSI / 3.0 8.46 1 1.624 107 D 1 ' S c Cd D 0.75 1.132 4.22 0.32TSI log10 215.63J D 0.75 18.42 E k 0.25 c 1472351.223 = 230680 N= = 6.38 yrs GO ON TO THE NEXT PAGE 11 CEE 362 - Homework #3 Solution Manual Flexible: 20 kip single = 1.47 42 kip tandem = 2.43 log10W18 = Z R So 9.36log10 SN 1 - 0.20 log10 PSI / 2.7 5.19 0.40 1094 SN 1 2.32 log10 M R 8.07 12 CEE 362 - Homework #3 Solution Manual Problem # 7: D = 11 in N =20 yrs = 600 p...
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This document was uploaded on 02/11/2014.

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