HW 3 solution

# 645 04 735log10 11 1 006 log10 17 30 846 1

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: GO ON TO THE NEXT PAGE 9 CEE 362 - Homework #3 W18 = < 6,567,920 Solution Manual under designed Try D= 12 inch log10W18 1.645 * 0.4 7.35log10 12 1 - 0.06 log10 1.7 / 3.0 8.46 1 1.624 107 12 1 600 * 0.9 120.75 1.132 4.22 0.32 * 2log10 215.63 * 3.2 120.75 18.42 5000000 2000.25 W18 = 6.9562 W18 = W18 = = 12 > 6,567,920 :) inch is adequate 10 CEE 362 - Homework #3 Solution Manual Problem # 6: =6* lb / TSI = 2.5 = 432 psi ΔPSI = 4.7-2.5 = 2.2 SN = 4 K = 190 lb / = 0.8 J = 0.3 D = 10 in Rigid: 20 kip single = 1.58 42 kip tandem = 4.74 log10W18 Z R S o 7.35log10 D 1 - 0.06 log10 PSI / 3.0 8.46 1 1.624 107 D 1 ' S c Cd D 0.75 1.132 4.22 0.32TSI log10 215.63J D 0.75 18.42 E k 0.25 c 1472351.223 = 230680 N= = 6.38 yrs GO ON TO THE NEXT PAGE 11 CEE 362 - Homework #3 Solution Manual Flexible: 20 kip single = 1.47 42 kip tandem = 2.43 log10W18 = Z R So 9.36log10 SN 1 - 0.20 log10 PSI / 2.7 5.19 0.40 1094 SN 1 2.32 log10 M R 8.07 12 CEE 362 - Homework #3 Solution Manual Problem # 7: D = 11 in N =20 yrs = 600 p...
View Full Document

## This document was uploaded on 02/11/2014.

Ask a homework question - tutors are online