3 cee 362 fall 2013 homework 6 solution manual problem

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Unformatted text preview: 3 - Homework # 6, Solution Manual Problem # 4 vehicle 13 veh time x 40 8 S= 3600 veh /h = 1 veh/s C = 60 sec 60 = r+t+8 equation 1 (r+t) = t equation 2 Solving equations 1 and 2 simultaneously: r= 26 sec t = 26 sec Thus the arrival time will be: 13 /26 = 0.5veh/s Arrival time = 1800 veh/h 4 CEE 362 – Fall 2013 - Homework # 6, Solution Manual Problem # 5 vehicle 2 vehicles Arrival Rate 10 veh S= 1800veh/h = 0.5 veh/s 4 veh time g r r + g = 80 sec equation 1 equation 2 Solving equations 1 and 2 simultaneously: r = 16 sec g = 64 sec =( ) - - ½ (64)*(64 *0.5+2-10) ½ (64) (64 * 0.5) = 112 +2176 ...
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This document was uploaded on 02/11/2014.

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