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HW 6 solutions

# HW 6 solutions - CEE 362 Fall 2013 Homework 6 Solution...

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CEE 362 Fall 2013 - Homework # 6, Solution Manual 1 Problem # 1 95 = n i = ci c c min s v X X L = C 1

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CEE 362 Fall 2013 - Homework # 6, Solution Manual 2 r g 10 S=1500/3600 A=800/3600 veh/sec Problem # 2 C = r+g+10 60 = r+g+10 equation 1 800 (r + g) = equation 2 Using equations 1 and 2: r = 23.3 sec g = 26.7 sec
CEE 362 Fall 2013 - Homework # 6, Solution Manual 3 40 x 0.4 veh/sec 0.2 veh/sec Problem # 3 Arrival rate = V = vehicle time 0.2 (40 + x) = 0.4 x X= 40 sec It takes 40 seconds for the queue to clear up after the green light starts.

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CEE 362 Fall 2013 - Homework # 6, Solution Manual 4 40 x 13 veh vehicle time 8 Problem # 4 S= 3600 veh /h = 1 veh/s C = 60 sec 60 = r+t+8 equation 1 (r+t) = t equation 2 Solving equations 1 and 2 simultaneously: r= 26 sec t = 26 sec Thus the arrival time will be: 13 /26 = 0.5veh/s Arrival time = 1800 veh/h
CEE 362 Fall 2013 - Homework # 6, Solution Manual 5 r g 10 veh vehicle time 4 veh Arrival Rate 2 vehicles S= 1800veh/h = 0.5 veh/s Problem # 5 r + g = 80 sec equation 1 equation 2 Solving equations 1 and 2 simultaneously: r = 16 sec g = 64 sec = ( ) -

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