HW 7 solutions - CEE 362 Fall 2013 Homework 7 Solution...

Info icon This preview shows pages 1–8. Sign up to view the full content.

View Full Document Right Arrow Icon
CEE 362 Fall 2013 - Homework # 7, Solution Manual 1 Problem # 1 B*Z = - 0.35 + 0.03*(5) +0.004*(150) - 0.10*(3.2) B*Z = 0.08 trips P (T>1) = 1 P (0) P (1) = 1- - = 1- 0.338 -0.367 P (T >1 ) = 0.295 i i e BZ
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
CEE 362 Fall 2013 - Homework # 7, Solution Manual 2 Problem # 2 = -0.543 (2.4) + 0.0165 (200) = 1.9968 = -0.543 (4.6) + 0.0165 (150) = -0.0228 = -0.543 (5.0) + 0.0165 (300) = 2.236 = -0.543 (8.7) + 0.0165 (600) = 5.1759 + + 194.645 = = = 0.03784 therefore trips to shopping center one: 0.3784 * 400 = 152 trips = = = 0.00502 therefore trips to shopping center two: 0.00502 * 400 = 20 trips = = = 0.04802 therefore trips to shopping center three: 0.04802 * 400 = 192 trips = = = 0.90912 therefore trips to shopping center four: 0.90912*400 = 3634 trips
Image of page 2
CEE 362 Fall 2013 - Homework # 7, Solution Manual 3 Problem # 3 Destination 1 = 0.17 (15.5) -0.23 (7.5) + 0.10 (5) = 1.41 Destination 2 = 0.17 (0.6) -0.23 (5.0) + 0.10 (10) = 0.87 Destination 3 = 0.17 (0.8) -0.23 (2.0) + 0.10 (8) = 0.476 Destination 4 = 0.17 (5.0) -0.23 (7.0) + 0.10 (15) = 0.74 Total = = + + + = + = = 0.4020 therefore trips to destination one: 0.4020 * 725 = 291 trips = = 0.2343 therefore trips to destination two: 0.2343 * 725 = 170 trips = = 0.1580 therefore trips to destination three: 0.1580 * 725 =
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 8
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern