Assignment Solutions_a6s

3 a 2 1 2 4 1 3 6 5 1 3 6 5 2 0 1 0 7 14

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Unformatted text preview: r4 − 5r2 4 a r4 + 2r1 0 10 a − 8 0 0 a+7 3 −4 2 −3 0 a+7 0 0 When a = −7, the rank of A is 2, otherwise, if a = −7, then the rank of A is 3. 3. (a) 2 −1 2 | −4 1 3 −6 | 5 1 3 −6 | 5 2 0| 1 → 0 −7 14 | −14 → 0 1 −2 | 2 . [A|b] = 3 1 3 −6 | 5 0 −7 18 | −14 00 4|0 So z = 0; Fromy − 2 = 2, =⇒ y = 2; From x + 3y − 6z = 5 =⇒ x = −1. Therefore, z −1 the solution is 2 . 0 (b) 1 1 2 −4 [A|b] = 5 11 2 5 11 0 6 → 0 0 00 | 2 1 0 | −1 → 0 | 8 | −3 0 7| 2 0| 5 → −42 | −7 19 −18 |...
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This note was uploaded on 02/13/2014 for the course MATH 2050 taught by Professor Dryuan during the Fall '12 term at Memorial University.

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