Spheres ams ams preflight6 preflight6 80 60 40 20 0 8

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Unformatted text preview: otential inversely proportional to the larger radius” (MRD) (MRD) Preflight 4 Preflight 4 100 80 60 40 20 0 7 “The potentials will be equal The because the wire makes the two spheres into one conductor.” spheres (AMS) (AMS) Preflight 6 Preflight 6 80 60 40 20 0 8 “The lower potential at A causes The charges from the higher potential from B to flow into A.” (CFL) from Preflight 8 Preflight 8 A small positive charge is placed near a conducting sphere with net negative small charge, -Q. Which of the following figures best represents the distribution of excess net negative charge as viewed from the center cross-section of the sphere. sphere. 70 • When +q moved near to conducting sphere, charges will move • How? • Negative charges in conductor will move toward +q • What determines the final distribution? • total E must be equal to zero in conductor • C and D are non­starters…. • A and B better, but excess charge must be on surface 60 50 40 30 20 10 0 Preflight 10 Preflight 10 BB THIS ONE WAS TOUGH THE PLAN: • I’ll show you some explanations • We’ll vote • We’ll do some work • We’ll vote again “Since the distance between plates decreases and the potential remains the same, then the Since charge increases, so Q1>Q0. Therefore, since the potential remains the same but the charge increases, the capacitance also increases, so C1>C0. “ increases, “Capacitance is only dependent on the geometry of the planes of the capacitator, therefore if Capacitance the distance separat...
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This document was uploaded on 02/13/2014.

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