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# Firstquestiondowehaveenoughsymmetrytousegausslaw

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Unformatted text preview: he right. “ pushing 40 “The positive electric fields in the Case B cancel out each other. The Thus, there is only eletric field going to the right at point P. There is eletric field going to the right at point P in Case A, as well. “ i27 s 10 30 20 0 P h y s ic s 2 1 2 Le c tu re 4 , S lid e 1 6 Superposition: NET + Case A 28 + - + Case B P h y s ic s 2 1 2 Le c tu re 4 , S lid e 1 7 BB Calculation y r2 neutral conductor +3Q A r1 x Point charge +3Q at center of neutral conducting shell of inner radius r1 and outer radius r2. a) What is E everywhere? First question: Do we have enough symmetry to use Gauss’ Law to determine E? Yes.. Spherical Symmetry (what does this mean???) B Magnitude of E is fcn of (r-r1) B Direction of E is along ˆ x ˆ y C Magnitude of E is fcn of (r-r2) C Direction of E is along ˆ r D None of the above D None of the above Magnitude of E is fcn of r A Direction of E is along P h y s ic s 2 1 2 Le c tu re 4 , S lid e 1 8 y BB Calculation Point charge +3Q at center of neutral conducting shell of inner rad...
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