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# Qm assumeqmedandx0areknown x02 exits here xxxxxxxxx x

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Unformatted text preview: ere x0/2 XXXXXXXXX X X X X X X X X X x0 XXXXXXXXX d XXXXXXXXX enters here B B What is B? E • What is v0, the speed of the particle as it enters the magnetic field ? v0 = 2E m v0 = 2qEd m v0 = 2ad v0 = 2qE md v0 = qEd m (A) (B) (C) (D) (E) • Why?? – Conservation of Energy • • Initial: Energy = U = qV = qEd Final: Energy = KE = ½ mv02 • • a = F/m = qE/m v02 = 2ad – Newton’s Laws 1 mv0 2 = qEd 2 qE v0 = 2 d m 2 v0 = v0 = 2qEd m 2qEd m BB Calculation Calculation A particle of charge q and mass m is accelerated from rest by an electric field E through a distance d and enters and exits a region containing a constant magnetic field B at the points shown. q,m Assume q,m,E,d, and x0 are known. x0/2 exits here XXXXXXXXX X X X X X X X X X x0 XXXXXXXXX d XXXXXXXXX enters here B B What is B? E • What is the path of the particle as it moves through the magnetic field? XXXXXXXXX XXXXXXXXX XXXXXXXXX XXXXXXXXX XXXXXXXXX XXXXXXXXX XXXXX XXXXXXXXX (A) (B) (C) X X X X • Why?? – XXXXXXXXX XXXXXXXXX XXXXXXXXX XXXXXXXXX Path is circle ! • • • Force is perpendicular to the velocity Force produces centripetal acc...
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