4 8 m b s 2 0 4 8 m c s 2 2 4 8 m d s 2 2 4

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Unformatted text preview: 2 m How does the s2’, the distance to the FINAL image, change? (A) s2’ inc re a s e s (B) s2’ d e c re a s e s s 1 =7 4 c m f=4 7 c m R ES ULT S s 1 ’ : 1 .4 3 m 1 .2 9 m s 2 ’ : 2 .6 9 m 1 .3 8 m (C ) s2’ re m a ins th e s a m e Step through images, one at a time WORDS Inc re a s ing s 1 will d e c re a s e s 1 ’ (m o ving c lo s e r to fo c a l p o int wo uld inc re a s e th e im a g e d is ta nc e ) De c re a s ing s 1 ’ will inc re a s e s 2 Inc re a s ing s 2 will d e c re a s e s 2 ’ EQUATIONS 111 =− s1′ f s1 s2 = 2m − s1′ 1 11 =− s2′ f s2 1 inc re a s e s s1′ s 2 inc re a s e s 1 inc re a s e s s2′ Multip le Le ns e s Exe rc is e s Multip Suppose we now decrease the initial object distance to 58 cm. Applying the lens equation, we find s 1’ = 2.4...
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This document was uploaded on 02/13/2014.

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