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Unformatted text preview: then s = 1.241224 = 1.114103. 1 (d) Yes. For example if 15 scores are 90 and 5 scores are 50 then X =
and the median is 90. (There are many possible examples.) 6. The sample size is 40 + 20 + Yi = 5 (Xi − 32) = −160 + 5 Xi . So Y =
10
5. The conversion is 20 + 9 + 10 = 100.
9
9
s2
Y = ( 5 )2 s2
X
9 = 25
81 · 16 = 400
81 and sY =  5 s2
9X = 5
9 ·4= 20
9. −160
9 1
20 (15 · 90 + 5 · 50) + 5X =
9 −160
9 = 80 ˙
+ 5 68 = 20;
9 (a) Note that regarding density, the bins are supposed to be consecutive, i.e. 0 − 49 actually means
6. The table below is − = 50.
[0, 50) and has length 50 the0data table completed with relative frequency and density. Note that
for the sake of simplicity, we decided to count 0 − 49 as a class of size 50. There are actually 50
Class Interval Frequency Rel.frequency
Density
possible integers in this box. (For the sake of grading, we could argue that this a continuous
40
0.4
interval [0,50) (size[0,50) [0,49] (size 49), which would .4 valid 50−0 = as.008
choices 0 well.)
049 50) or
40
100 = 0 be
20 0 .2 5069 [50,70)
20
Class interval Frequency Relative Frequency = 0.2
100 Density
70−50...
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This document was uploaded on 02/15/2014 for the course MATH 231 at Lehigh University .
 Fall '11
 DANIELCONUS
 Statistics

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