There are many possible examples 6 the sample size is

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Unformatted text preview: then s = 1.241224 = 1.114103. 1 (d) Yes. For example if 15 scores are 90 and 5 scores are 50 then X = and the median is 90. (There are many possible examples.) 6. The sample size is 40 + 20 + Yi = 5 (Xi − 32) = −160 + 5 Xi . So Y = 10 5. The conversion is 20 + 9 + 10 = 100. 9 9 s2 Y = ( 5 )2 s2 X 9 = 25 81 · 16 = 400 81 and sY = | 5 |s2 9X = 5 9 ·4= 20 9. −160 9 1 20 (15 · 90 + 5 · 50) + 5X = 9 −160 9 = 80 ˙ + 5 68 = 20; 9 (a) Note that regarding density, the bins are supposed to be consecutive, i.e. 0 − 49 actually means 6. The table below is − = 50. [0, 50) and has length 50 the0data table completed with relative frequency and density. Note that for the sake of simplicity, we decided to count 0 − 49 as a class of size 50. There are actually 50 Class Interval Frequency Rel.frequency Density possible integers in this box. (For the sake of grading, we could argue that this a continuous 40 0.4 interval [0,50) (size[0,50) [0,49] (size 49), which would .4 valid 50−0 = as.008 choices 0 well.) 0-49 50) or 40 100 = 0 be 20 0 .2 50-69 [50,70) 20 Class interval Frequency Relative Frequency = 0.2 100 Density 70−50...
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This document was uploaded on 02/15/2014 for the course MATH 231 at Lehigh University .

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