EECE 363 Quiz 4B 2008 Solutions

25mav21ma12 1 mav rin 1gm 1 k for rout short

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Unformatted text preview: = 2V) ∴Saturation -5- Question 4, Cont’d. (b) Sketch a “T” equivalent small signal circuit for the amplifier. (3 points) or equivalent. (c) Find the expressions for the input resistance Rin and the output resistance Rout as indicated in the circuit. Calculate their numerical values. (3 points) gm = (4KnID)1/2 = [4(0.25mA/V2)(1mA)]1/2 = 1 mA/V Rin = 1/gm = 1 kΩ For Rout, short circuiting vs results in vgs = 0 V, i.e., id = gmvgs = 0 A or D is open circuit. ∴Rout = RD = 5 kΩ -6- Question 4, Cont’d. (d) Derive an ex...
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This document was uploaded on 02/16/2014 for the course EECE 363 at University of British Columbia.

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