PREC11 Unit1 notes

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Unformatted text preview: inimum value of −36 domain: {x| x ∈ } range:{y| y ≤ −36, y∈ } no x-intercepts 5. a) y = (x + 3)2 − 5 b) y = −2(x − 1)2 + 12 c) y = d) y = − 1 (x + 3)2 + 4 4 6. a) y = − 1 x2 4 b) y = 3x2 − 6 c) y = −4(x − 2)2 + 5 e) y = − 3 ( x − 6 ) 2 + 3 0 2 f) y = 3 8 1 2 (x − 3 )2 + 1 d) y = 1 5 (x + 3)2 − 10 (x + 13)2 − 24 7. a) (4,16)→(−1,16)→(−1,24) b) (4,16)→(4,−16)→(4,−4) c) (4,16)→(4,−16)→(14,−16) b) (4,16)→(4,48)→(4,40) 8. Re-write the equation as y = −5x2 + 20, so a = −5 , p = 0 , and q = 20. Starting with the graph of y = x2, reflect the graph in the x-axis, expand it away from the x-axis by a factor of 5, and then translate the entire new graph up 20 units. 9. Quadratic functions all have domain {x| x ∈ }, so 0 will be a value that can be used as an x-coordinate. Each value from the domain of any function can be paired with exactly one y-coordinate. There can then be exactly one point with 0 as its x-coordinate, therefore al...
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This document was uploaded on 02/16/2014 for the course MATH Pre-Calcul at Holy Cross Regional High School.

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