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Unformatted text preview: , or (15,−100).
b) For the function f(x) = 5(x − 15)2 − 100, p = 15. The equation of the axis of symmetry is x = p, or x = 15 .
c) For the function f(x) = 5(x − 15)2 − 100, a = 5. Since a > 0, the graph opens upward.
d) Since the graph of the function opens upward, it has a minimum value of q, or −100.
e) The domain is {x x∈ }. Since the graph has a minimum value of −100, the range is {y y ≥ −100, y∈ }.
f) Since the graph's vertex is below the xaxis and it opens upward, there are two xintercepts.
4. a) vertex: (0,14)
axis of symmetry: x = 0
opens downward
maximum value of 14
domain: {x x ∈ }
range: {y y ≤ 14, y∈ }
two xintercepts b) vertex: (−18,−8)
c) vertex: (7,0)
axis of symmetry: x = −18
axis of symmetry: x = 7
opens upward
opens upward
minimum value of −8
minimum value of 0
domain: {x x ∈ }
domain: {x x ∈ }
range: {y y ≥ −8, y∈ }
range: {y y ≥ 0, y∈ }
two xintercepts
one xintercept d) vertex: (−4,−36)
axis of symmetry: x = −4
opens downward
m...
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This document was uploaded on 02/16/2014 for the course MATH PreCalcul at Holy Cross Regional High School.
 Fall '11
 Aytona
 Calculus, PreCalculus, Polynomials

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