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PREC11 Unit1 notes

# A y x 32 5 b y 2x 12 12 c y d y 1

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Unformatted text preview: , or (15,−100). b) For the function f(x) = 5(x − 15)2 − 100, p = 15. The equation of the axis of symmetry is x = p, or x = 15 . c) For the function f(x) = 5(x − 15)2 − 100, a = 5. Since a > 0, the graph opens upward. d) Since the graph of the function opens upward, it has a minimum value of q, or −100. e) The domain is {x| x∈ }. Since the graph has a minimum value of −100, the range is {y| y ≥ −100, y∈ }. f) Since the graph's vertex is below the x-axis and it opens upward, there are two x-intercepts. 4. a) vertex: (0,14) axis of symmetry: x = 0 opens downward maximum value of 14 domain: {x| x ∈ } range: {y| y ≤ 14, y∈ } two x-intercepts b) vertex: (−18,−8) c) vertex: (7,0) axis of symmetry: x = −18 axis of symmetry: x = 7 opens upward opens upward minimum value of −8 minimum value of 0 domain: {x| x ∈ } domain: {x| x ∈ } range: {y| y ≥ −8, y∈ } range: {y| y ≥ 0, y∈ } two x-intercepts one x-intercept d) vertex: (−4,−36) axis of symmetry: x = −4 opens downward m...
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