PREC11 Unit1 notes

# Upward minimum value of 2 domain x x range y y 2

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Unformatted text preview: expand the graph away from the x-axis by a factor of 5 and translate the entire new graph 20 units to the left and 21 units down. d) Given the graph of y = x2, reflect the graph in the x-axis and compress the graph towards the x-axis by a factor of ⅛ and translate the entire new graph 5.6 units to the right and 13.8 units up. y 2. a) b) y c) y 8 d) y 10 8 10 6 8 6 8 4 6 4 6 2 4 2 4 0 2 4 6 2 x −2 vertex: (3,9) axis of symmetry: x = 3 opens downward maximum value of 9 domain: {x| x ∈ } range: {y| y ≤ 9, y∈ } x-intercepts: (0,0), (6,0) y-intercept: (0,0) −2 2 −8 −6 −4 −2 0 2 4 x −2 x vertex: (−4,1) axis of symmetry: x = −4 opens upward minimum value of 1 domain: {x| x ∈ } range: {y| y ≥ 1, y∈ } no x-intercepts y-intercept: (0,5) 0 −2 0 2 4 x vertex: (1,12) axis of symmetry: x = 1 opens downward maximum value of 12 domain: {x| x ∈ } range: {y| y ≤ 12, y∈ } x-intercepts: (−1,0), (3,0) y-intercept: (0,9) vertex: (2,−2) axis of symmetry: x = 2 opens upward minimum value of −2 domain: {x| x ∈ } range: {y| y ≥ −2, y∈ } x-intercepts: (0,0), (4,0) y-intercept: (0,0) 3. a) For the function f(x) = 5(x − 15)2 − 100, p = 15 and q = −100. The vertex is located at (p,q)...
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## This document was uploaded on 02/16/2014 for the course MATH Pre-Calcul at Holy Cross Regional High School.

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