Ch 23 - The Evolution of Populations (1 slide per page)-1

11 11 explanation of the hardy weinberg equilibrium 2

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Unformatted text preview: pulation btwn generations unless outside forces act to change those frequencies. 11 11 Explanation of the Hardy Weinberg Equilibrium 2 alleles of a gene • No webbing (W) (dominant) • Webbing (w) (recessive) 12 12 Phenotypes Genotypes WW Ww ww Number of animals (total = 500) 320 160 20 Genotype frequencies 320 ––– 500 Number of alleles in gene pool (total = 1,000) Allele frequencies 160 ––– 500 = 0.64 640 W = 0.32 160 W + 160 w 800 p= 1,000 = 0.8 W 20 ––– 500 = 0.04 40 w 200 q= 1,000 = 0.2 w 14 14 Phenotypes Genotypes WW Ww ww Number of animals (total = 500) 320 160 20 Genotype frequencies 320 ––– 500 Number of alleles in gene pool (total = 1,000) Allele frequencies 160 ––– 500 = 0.64 640 W = 0.32 160 W + 160 w 800 p= 1,000 = 0.8 W 20 ––– 500 = 0.04 40 w 200 q= 1,000 = 0.2 w 15 15 Phenotypes Genotypes WW Ww ww Number of animals (total = 500) 320 160 20 Genotype frequencies 320 ––– 500 Number of alleles in gene pool (total = 1,000) Allele frequencies 160 ––– 500 = 0.64 640 W = 0.32 160 W + 160 w 800 p= 1,000 = 0.8 W 20 ––– 500 = 0.04 40 w 200 q= 1,000 = 0.2 w 16 16 Phenotypes Genotypes WW Ww ww Number of animals (total = 500) 320 160 20 Genotype frequencies 320 ––– 500 160 ––...
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This note was uploaded on 02/12/2014 for the course BIOLOGY 2011 taught by Professor Woo during the Fall '10 term at University of Central Florida.

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