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Unformatted text preview: particles •  F=ma, •  •  Δv a= Δt kq1q2 Coulomb’s law gives F = 2 r kq1q2 So F = = ma 2 r January 22, 2014 Physics 104, Spring 2014 18 Electric Field •  •  •  •  What is it? Field lines around charges Superposition of electric field vectors Field lines near a conductor January 22, 2014 Physics 104, Spring 2014 19 Electric Field A charged particle creates an electric field. Direction of this field is the direction of the force on positive (+) “test” charge. FC Q E= =k 2 qt r Qp=1.6x10-19 C E + r = 1x10-10 m –  qt (test charge) –  E Field (independent of test charge) –  F = qE (1.6 × 10 ) N ) (10 ) −19 ( E = 9 × 10 9 January 22, 2014 −10 2 = 2.9 × 1011 N/C (to the right) Physics 104, Spring 2014 20 32 x 1011 N/C Electric Field of a Point Charge + 2.9 x 1011 N/C E This is becoming a mess!!! January 22, 2014 Physics 104, Spring 2014 21 Electric Field 1.  Density gives strength # lines proportional to Q lines never cross! 2.  Arrow gives direction Start on +, end on - January 22, 2014 Physics 104, Spring 2014 22 Electric Field Patterns Point charge •  The lines radiate equally in all directions •  For a positive source charge, the lines will radiate outward January 22, 2014 Physics 104, Spring 2014 23 Electric Field Patterns •  For a negative source charge, the lines will point inward January 22, 2014 Physics 104, Spring 2014 24 Principle of superposition •  What is the electric force due to multiple charged particles? •  Calculate the force on a test charge due t...
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This note was uploaded on 02/14/2014 for the course PHYSICS 103 taught by Professor Citrinini during the Spring '09 term at University of Wisconsin.

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