MATH 1071 ProbabilityBasic_11:28

# 30 p f 51 p e f 70 1 2 3 p e 0 f p e

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Unformatted text preview: P (E [ F ) P (E ) = .40 P (E 0 [ F 0 ) = P ((E \ F )0 ) = 1 P (F 0 ) = 1 P (F ) = .49 .7-.3=.4 P (E \ F ) = .89 p(eUf)= .11 probability of everything has to add up to 1 Patrick Newberry Basic Concepts of Probability November 28, 2012 7 / 10 70 ------140 = 1 -----2 Odds Notes Deﬁnition The odds in favor of an event E are deﬁned as the ratio of P (E ) to P (E 0 ) (for P (E 0 ) 6= 0) p(7)+p(11)/ 1-(p(7)-p(11) P (E ) or P (E ) : P (E 0 ) P (E 0 ) recovering the probablity -divid by the sum of the numerator and denominator 2/7-> prob = (2/9)/(7/9) Two dice are rolled. 1 What are the odds of rolling a 7 or 11. 6 36 1 2 + 6 36 2 36 + 2 36 = 2 )2:7 7 What are the odds in favor of not rolling doubles? 30 36 6 36 Patrick Newberry = 5 )5:1 1 Basic Concepts of Probability November 28, 2012 8 / 10 Odds Notes Clicker Check-out: Choose any letter to check out now. Recitation Thursday: Quiz 6: Sections 7.1-7.3, 8.1, 8.2 Next Time: Section 8.5: Conditional Probability Patrick Newberry Basic Concepts of Probability November 28, 2012 10 / 10 Notes...
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## This document was uploaded on 02/18/2014 for the course MATH 1071 at Colorado.

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