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Unformatted text preview: P (E [ F ) P (E ) = .40 P (E 0 [ F 0 ) = P ((E \ F )0 ) = 1
P (F 0 ) = 1 P (F ) = .49 .7.3=.4 P (E \ F ) = .89 p(eUf)= .11 probability of everything has to add up to 1
Patrick Newberry Basic Concepts of Probability November 28, 2012 7 / 10 70
140 = 1
2 Odds Notes Deﬁnition
The odds in favor of an event E are deﬁned as the ratio of P (E ) to
P (E 0 ) (for P (E 0 ) 6= 0) p(7)+p(11)/ 1(p(7)p(11) P (E )
or P (E ) : P (E 0 )
P (E 0 ) recovering the probablity
divid by the sum of the numerator and
denominator
2/7> prob = (2/9)/(7/9) Two dice are rolled.
1
What are the odds of rolling a 7 or 11.
6
36 1
2 +
6
36 2
36 + 2
36 = 2
)2:7
7 What are the odds in favor of not rolling doubles?
30
36
6
36
Patrick Newberry = 5
)5:1
1 Basic Concepts of Probability November 28, 2012 8 / 10 Odds Notes Clicker Checkout: Choose any letter to check out now.
Recitation Thursday: Quiz 6: Sections 7.17.3, 8.1, 8.2
Next Time: Section 8.5: Conditional Probability Patrick Newberry Basic Concepts of Probability November 28, 2012 10 / 10 Notes...
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This document was uploaded on 02/18/2014 for the course MATH 1071 at Colorado.
 Fall '08
 MARSHALL,K
 Math, Probability

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