MATH 1071 VennDiagrams_11:14

64 had a cat 28 had a dog and a cat 84 had neither a

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Unformatted text preview: eet. 6 had a cat, a dog, and a parakeet. How many had a parakeet only? n(U ) = 220 n(D ) = 83 n(C ) = 64 n(D \ C ) = 28 n(D 0 \ C 0 \ P 0 ) = 84 n (D \ C \ D ) = 6 n(D 0 \ C 0 \ P ) =? Patrick Newberry Venn Diagrams Cardinality November 14, 2012 12 / 14 Examples Notes PC D6 D0 Tot C0 17 Tot P 0 C C 0 Tot D 22 D0 84 Tot n (D 0 \ C 0 \ P ) = n (D 0 \ C 0 ) = (n ( U ) Tot C C 0 Tot D 28 55 83 D 0 36 101 137 Tot 64 156 220 n (D 0 \ C 0 \ P 0 ) n(D [ C )) = 220 = 220 (83 + 64 84 (n (D ) + n (C ) 28) n(D \ C )) 84 84 = 17 Patrick Newberry Venn Diagrams Cardinality November 14, 2012 13 / 14 Examples Notes Clicker Check-out: Choose any letter to check out now. Recitation Thursday: Workshop 6 Next Time: Section 8.3: Introduction to Probability Patrick Newberry Venn Diagrams November 14, 2012 14 / 14...
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